Barbara Posted January 30, 2007 Posted January 30, 2007 .The definition of insanity is doing the same thing over and over and expecting a different result. (And I didn't triple space)
Ferhat Yalcin Posted January 30, 2007 Posted January 30, 2007 i... can't...help...myself.... can I help you ?
Scott Johnston Posted January 30, 2007 Posted January 30, 2007 This is how we do it........ This is how we do it........ This is how we do it........ can I help you ? can I help you ? can I help you ? can I help you ? can I help you ?
ManekiNeko Posted January 30, 2007 Posted January 30, 2007 Poor triple spacing. I hope someone calls it in the morning.
jparrott Posted January 30, 2007 Posted January 30, 2007 I believe the standard process for organizing a large chorus of outlaw eunuchs is Try, Pile, Spay, Sing.
jpschust Posted January 30, 2007 Posted January 30, 2007 Poor triple spacing. I hope someone calls it in the morning.Don't pity it. It was asking for it anyways- I mean just look at how much clevage it shows.
DonRocks Posted January 30, 2007 Author Posted January 30, 2007 Actually, if anyone on the board sees a triple-spaced post, would you please cut-and-paste the URL of the post, and PM the poster? Thanks. And I'm sorry if I'm cranky, but I'm working on a problem right now. In fact, I could use some help. If anyone can get me the answer, I'll take them out to dinner at Maestro. Anyway, I need f (4, 2) resolved to an integer value for the following function: ------------------------------------------------------ f (x, y) = y + 1 ........................ {when x = 0} f (x-1, 1) ................... {when x > 0 and y = 0} f (x-1, f (x, y-1)) ........ {when x > 0 and y > 0) ------------------------------------------------------- It seems pretty simple, so probably won't take too long to resolve. Nevertheless, I can't seem to get the answer, and am willing to pay accordingly to the first person who can get it solved. First person to PM me the answer gets it. Thanks! Rocks
Seanchai Posted January 30, 2007 Posted January 30, 2007 Actually, if anyone on the board sees a triple-spaced post, would you please cut-and-paste the URL of the post, and PM the poster? Thanks.And I'm sorry if I'm cranky, but I'm working on a problem right now. In fact, I could use some help. If anyone can get me the answer, I'll take them out to dinner at Maestro. Anyway, I need f (4, 2) resolved to an integer value for the following function: ------------------------------------------------------ f (x, y) = y + 1 ........................ {when x = 0} f (x-1, 1) ................... {when x > 0 and y = 0} f (x-1, f (x, y-1)) ........ {when x > 0 and y > 0) ------------------------------------------------------- It seems pretty simple, so probably won't take too long to resolve. Nevertheless, I can't seem to get the answer, and am willing to pay accordingly to the first person who can get it solved. First person to PM me the answer gets it. Thanks! Rocks I was told that there would be no math in this debate ...
chef4cook Posted January 30, 2007 Posted January 30, 2007 Actually, if anyone on the board sees a triple-spaced post, would you please cut-and-paste the URL of the post, and PM the poster? Thanks.And I'm sorry if I'm cranky, but I'm working on a problem right now. In fact, I could use some help. If anyone can get me the answer, I'll take them out to dinner at Maestro. Anyway, I need f (4, 2) resolved to an integer value for the following function: ------------------------------------------------------ f (x, y) = y + 1 ........................ {when x = 0} f (x-1, 1) ................... {when x > 0 and y = 0} f (x-1, f (x, y-1)) ........ {when x > 0 and y > 0) ------------------------------------------------------- It seems pretty simple, so probably won't take too long to resolve. Nevertheless, I can't seem to get the answer, and am willing to pay accordingly to the first person who can get it solved. First person to PM me the answer gets it. Thanks! Rocks I suck at math. What are the letters doing in there?
B.A.R. Posted January 30, 2007 Posted January 30, 2007 The answer is 11. I am available for dinner Friday.
jparrott Posted January 30, 2007 Posted January 30, 2007 f(x, y) = y + 1 ........................ {when x = 0} f(x - 1, 1) ................... {when x > 0 and y = 0} f(x - 1, f(x, y - 1)) ........ {when x > 0 and y > 0) f(0, y) = 1 + y Using induction to prove f(1, y) = y +2: Base case: f(1, 0) = f(0, 1) = 2 = 0 + 2 Assume for particular but arbitrarily chosen (pbac) k that it is true for (k - 1) then show for k: f(1, k) = f(0, f(1, k - 1)) = 1+ f(1, k - 1) = 1 + [(k - 1) + 2] = k + 2 QED. Using induction to prove f(2, y) = 2y + 3: Base case: f(2, 0) = f(1, 1) = 3 Assume for pbac k that it is true for (k - 1) then show for k: f(2, k) = f(1, f(2, k - 1)) = 2 + f(2, k - 1) = 2 + 2(k-1) + 3 = 2 + 2k - 2 + 3 = 2k + 3 QED. Using induction to prove f(3, y) = 23 + y - 3: Base case: f(3, 0) = f(2, 1) = 5 = 23 + 0 - 3 Assume for pbac k that it is true for (k - 1) then show for k: f(3, k) = f(2, f(3, k - 1)) = f(2, 23 + k - 1 - 3) = 2 * (23 + k - 1 - 3) + 3 = 2 * (2k + 2 - 3) + 3 = 2k + 3 - 6 + 3 = 2k + 3 - 3 QED. Calculating f(4, 2): f(4, 0) = f(3, 1) = 13 f(4, 1) = f(3, f(4, 0)) = f(3, 13) = 216 - 3 = 65533 f(4, 2) = f(3, f(4, 1)) = f(3, 65533) = 265536 - 3
DonRocks Posted January 30, 2007 Author Posted January 30, 2007 2^65536 - 3 Thanks. Now I'll just need you to PM me the integer (not an equation) and I'll take you to Maestro. And I'll buy you dessert if you PM me the answer to f (4, 3). Of course, there are more digits in that answer than there are particles in the known universe. And the only number I know of that's larger than this is THE NUMBER OF POSTS THAT I'VE EDITED IN THE PAST 21 MONTHS THAT HAVE BEEN TRIPLE-SPACED. Please stop triple-spacing! And if you're curious, click here to learn more about the imposing Ackermann function. (Oh, and Jake, I have to say ... pretty impressive.)
jparrott Posted January 30, 2007 Posted January 30, 2007 Note also that Ack(4, 2) = 22^16 - 3 or F16 - 4, where F1, F2, Fn are the Fermat numbers. Fun stuff.
jparrott Posted January 30, 2007 Posted January 30, 2007 Thanks. Now I'll just need you to PM me the integer (not an equation) and I'll take you to Maestro.Binary: 265536 is a 1 with 65536 zeroes after, 265536 - 1 is 65536 ones, so 265536 - 3 is 65534 ones, then a zero, then a one.Hex: 265536 is 1616384 or a 1 with 16384 zeroes after, so 265546 - 3 is 16383 F's, then one D.
Antonio Burrell Posted January 30, 2007 Posted January 30, 2007 Man, should I send it to him in Binary? Or Hex?You're such a nerd edited to eliminate triple spacing, I think
Al Dente Posted January 30, 2007 Posted January 30, 2007 Note also that Ack(4, 2) = 2^(2^16) - 3 or F_16 - 4, where F_1, F_2, F_n are the Fermat numbers. Fun stuff. Ack =
shogun Posted January 30, 2007 Posted January 30, 2007 well, vienna sausages in a can.This one time I was at the 7-11 by Foggy Bottom Metro, and there was a guy standing outside with a bag and a soda. He produced a can of Vienna sausages, popped it open, and proceeded to drink the liquid from the can. That accomplished, he ate the sausages.
B.A.R. Posted January 30, 2007 Posted January 30, 2007 f (x, y) = y + 1 ........................ {when x = 0} f (x-1, 1) ................... {when x > 0 and y = 0} f (x-1, f (x, y-1)) ........ {when x > 0 and y > 0) f(0, y) = 1 + y Using strong induction to prove f(1, y) = y +2: Base case: f(1, 0) = f (0, 1) = 2 = 0 + 2 f(1, 1) = f (0, f (1, 0)) = f(0, f(0, 1)) = f (0, 2) = 3 = 1 + 2 Assume for all k = 2 to y-1 that it is true then show for y: f(1, y) = f(0, f(1, y-1)) = 1+ f(1, y-1) = 1 + [(y - 1) + 2] = y + 2 QED.......................f(4, 2) = f(3, f(4, 1)) = f(3, 65533) = 2^65536 - 3 I stand by 11.
jparrott Posted January 30, 2007 Posted January 30, 2007 I stand by 11.Interesting. I think most folks would double down on eleven.
jpschust Posted January 30, 2007 Posted January 30, 2007 Interesting. I think most folks would double down on eleven.really? on a yo the house has 11.11 percent odds.
jparrott Posted January 30, 2007 Posted January 30, 2007 I'll pay for dessert. Note that Ack(4, 3) has about the same number of digits as the number in the attached file. Ackerman_4_2.pdf
DonRocks Posted January 30, 2007 Author Posted January 30, 2007 I'll pay for dessert. Note that Ack(4, 3) has about the same number of digits as the number in the attached file. I specifically said "PM me the integer" for a reason. This is not a PM.
Pat Posted January 31, 2007 Posted January 31, 2007 Sent.Congratulations if you got something to go through as a PM that's 19,000+ characters long.
DonRocks Posted January 31, 2007 Author Posted January 31, 2007 Well I'll be a son of a bitch. He did it.
DonRocks Posted January 31, 2007 Author Posted January 31, 2007 Is that what shut the site down? I just spent ten dollars on additional bandwidth to get us through January. That's an app. Not an applet; an appetizer. Fucking Parrott has no life, chewed up his employer's CPU all afternoon computing a 19,000-digit number, and cost me an order of mozzarella sticks.
ScotteeM Posted January 31, 2007 Posted January 31, 2007 I just spent ten dollars on additional bandwidth to get us through January. That's an app. Not an applet; an appetizer. Fucking Parrott has no life, chewed up his employer's CPU all afternoon computing a 19,000-digit number, and cost me an order of mozzarella sticks. Next time I see you, I'll buy you some! ETA: I was right to be afraid of all those numbers and letters!
DanielK Posted January 31, 2007 Posted January 31, 2007 Well I'll be a son of a bitch. He did it. Jake, you're my freaking hero.
ScotteeM Posted January 31, 2007 Posted January 31, 2007 Maybe we need an admissions test for DR.com: anyone who can solve that sort of problem can't be a member, lest they tie us all up in knots. And, Don, don't blame yourself for asking the question, when I'm sure you thought no one could answer it.
johnb Posted January 31, 2007 Posted January 31, 2007 I just spent ten dollars on additional bandwidth to get us through January. That's an app. Not an applet; an appetizer. Fucking Parrott has no life, chewed up his employer's CPU all afternoon computing a 19,000-digit number, and cost me an order of mozzarella sticks. I presume those are some of Fabio's Maestro mozzarella sticks.
Jacques Gastreaux Posted January 31, 2007 Posted January 31, 2007 I just spent ten dollars on additional bandwidth to get us through January. That's an app. Not an applet; an appetizer. Fucking Parrott has no life, chewed up his employer's CPU all afternoon computing a 19,000-digit number, and cost me an order of mozzarella sticks.It's the old addage, be careful what you ask for. And also, rocks needed to spend $10 to get us through January, which ends tomorrow. I hope they had internet access at whatever bar he was in when he got word that the site was down.ETA: And I can just see the shit eating grin that must have been on Jake's face when he hit the send button on that PM.
CrescentFresh Posted January 31, 2007 Posted January 31, 2007 It's the old addage, be careful what you ask for. And also, rocks needed to spend $10 to get us through January, which ends tomorrow. I hope they had internet access at whatever bar he was in when he got word that the site was down. It's tomorrow. And the answer to life, the universe, and everything is actually 42.
edenman Posted January 31, 2007 Posted January 31, 2007 Please Stop Triple Spacing, Otherwise Jake Parrott will [make you buy him a meal at Maestro]
Halloween Posted January 31, 2007 Posted January 31, 2007 f (x, y) = y + 1 ........................ {when x = 0} f (x-1, 1) ................... {when x > 0 and y = 0} f (x-1, f (x, y-1)) ........ {when x > 0 and y > 0) f(0, y) = 1 + y Using strong induction to prove f(1, y) = y +2: Base case: f(1, 0) = f (0, 1) = 2 = 0 + 2 f(1, 1) = f (0, f (1, 0)) = f(0, f(0, 1)) = f (0, 2) = 3 = 1 + 2 Assume for all k = 2 to y-1 that it is true then show for y: f(1, y) = f(0, f(1, y-1)) = 1+ f(1, y-1) = 1 + [(y - 1) + 2] = y + 2 QED. Using strong induction to prove f(2, y) = 2y + 3 Base cases: f(2, 0) = f(1, 1) = 3 f(2, 1) = f(1, f(2, 0)) = f(2, 0) + 2 = 5 = 2(1) + 3 Assume for all k = 2 to y-1 that it is true then show for y: f (2, y) = f(1, f(2, y-1)) = 2 + f(2, y-1) = 2 + 2(y-1) + 3 = 2 + 2y - 2 + 3 = 2y + 3 QED. Using strong induction to prove f(3, y) = 2^(3+y) - 3 [where 2^x denotes 2 raised to the power of x]: Base case: f(3, 0) = f (2, 1) = 5 = 2^(3+0) - 3 f(3, 1) = f (2, f(3, 0)) = f (2, 5) = 13 = 2^(3+1)-3 Assume for all k=0 to y-1 that f (3, k) = 2^(3+k) - 3. Now prove for y. f(3, y) = f(2, f(3, y-1)) = f(2, 2^(3+y-1) - 3) = 2{[2^(3+y-1)] - 3] + 3 = 2* {[2^(y+2)] - 3} + 3 = 2^(y+3) - 6 + 3 = 2^(y+3) - 3 QED. f(4, 0) = f(3, 1) = 13 f(4, 1) = f(3, f(4, 0)) = f(3, 13) = (2^16)-3 = 65533 f(4, 2) = f(3, f(4, 1)) = f(3, 65533) = 2^65536 - 3 Uhhhh. Que???!!!
jparrott Posted January 31, 2007 Posted January 31, 2007 And I can just see the shit eating grin that must have been on Jake's face when he hit the send button on that PM. Actually, I was quite amused that such a tool existed!Fucking Parrott has no lifeGuilty. Or are you talking about my long-lost second cousin, eleven times removed? chewed up his employer's CPU all afternoon computing a 19,000-digit numberActually, it took about a minute on a Dell Latitude D505 laptop.cost me an order of mozzarella sticks.I wonder. What would Vincent Feraud propose alongside some nice fritti da mozzarella?
crackers Posted January 31, 2007 Posted January 31, 2007 If this dish is on the menu six months from now at $20, and has the same quantity and quality of ingredients, I'll run down K Street with no clothes on during rush hour.Cheers, Rocks. Go Jake! Enjoy your dinner at Maestro (go sooner rather than later, I would advise.) Aren't you glad he wagered a meal at Maestro, and not the above? BTW, has anybody checked the menu at Blue Duck Tavern recently?
jparrott Posted January 31, 2007 Posted January 31, 2007 Sadly, this particular meat-and-two-veg is not on the current online menu.
DanCole42 Posted January 31, 2007 Posted January 31, 2007 This whole thing goes well beyond the Algebra 2 level of education I attained in high school. e^i(pi) = -1 I have a file on my computer of pi to 10 million digits. I like to see how many times my phone number appears in it (twice), and friends' birthdays. Mmmmmmm.... pie.....
Jacques Gastreaux Posted January 31, 2007 Posted January 31, 2007 Jake, I'm glad to see that that MIT education of yours is starting to pay off. ETA: There are 19,729 digits in that number. It takes up 6 pages in a Word document.
ol_ironstomach Posted January 31, 2007 Posted January 31, 2007 That, and be glad that Rocks didn't pose his (solvable) challenge using sets of timed Putnam competition questions... (eta: the decimal calculation runs in about five seconds flat using this Java-based bignum calc)
Barbara Posted January 31, 2007 Posted January 31, 2007 Question: Just what exactly is wrong with post #31 on this thread?
jparrott Posted January 31, 2007 Posted January 31, 2007 ETA: There are 19,729 digits in that number. It takes up 6 pages in a Word document.I thought I had posted that earlier, but it was removed in a fit of pique--the moderator spilled Vietnamese beef stew on his coarsely-knit polo shirt.Note, of course, that you can calculate the number of digits without writing out the number by taking the base-10 logarithm: log10265536 = 65536 * log102 ~= 65536 * 0.30103 ~= 19728.3and rounding up.
cjsadler Posted January 31, 2007 Posted January 31, 2007 Nerds and Rachael Ray lust-ers... I knew it!
RRSmith Posted February 1, 2007 Posted February 1, 2007 THE NUMBER OF POSTS THAT I'VE EDITED IN THE PAST 21 MONTHS THAT HAVE BEEN TRIPLE-SPACED.Please stop triple-spacing! OK, I'm confused. We were PM'd that we were guilty of triple spacing. Are we talking actual triple spaces, or are we talking ellipsis'? I know I'm a big ellipsis user. Is this what is causing all the grief?
Barbara Posted February 1, 2007 Posted February 1, 2007 OK, I'm confused. We were PM'd that we were guilty of triple spacing. Are we talking actual triple spaces, or are we talking ellipsis'? I know I'm a big ellipsis user. Is this what is causing all the grief?Answer: Rocks himself ( ) triple-spaced in post #31. It fascinates me that NOBODY, including Rocks his ownself, picked up on this. Thus making this whole subject completely irrelevant.ETA: WELCOME, RRSMITH, to our merry, if somewhat confused, band.
Jacques Gastreaux Posted February 1, 2007 Posted February 1, 2007 OK, I'm confused. We were PM'd that we were guilty of triple spacing. Are we talking actual triple spaces, or are we talking ellipsis'? I know I'm a big ellipsis user. Is this what is causing all the grief?Your post is a classic example of a triple space violation.
ol_ironstomach Posted February 1, 2007 Posted February 1, 2007 Answer: Rocks himself ( ) triple-spaced in post #31. It fascinates me that NOBODY, including Rocks his ownself, picked up on this. Nobody picked up on that because post #31 is only doublespaced!
Mark Slater Posted February 1, 2007 Posted February 1, 2007 Your post is a classic example of a triple space violation. Could someone remind me why this is important or why anyone cares? Does Rocks pay for this dartboard by the space?
Meaghan Posted February 1, 2007 Posted February 1, 2007 Could someone remind me why this is important or why anyone cares? Does Rocks pay for this dartboard by the space? Amen. He trades in excess white space in Invisionland for U.S. postal stamps.
Poivrot Farci Posted February 1, 2007 Posted February 1, 2007 Note that Ack(4, 3) has about the same number of digits as the number in the attached file.My results were similar, using little more than a jade abacus, Casio wrist-watch and physics post-doc nerd friend from Rockefeller U.Is there a runner-up silver burrito offer? mathing.pdf
monsterriffs Posted July 20, 2007 Posted July 20, 2007 OK, I'm confused. We were PM'd that we were guilty of triple spacing. Are we talking actual triple spaces, or are we talking ellipsis'? I know I'm a big ellipsis user. Is this what is causing all the grief? The input area where you type your post is a bit wonky, so, if you hit return to put a space between the quote section and what you're typing, it actually comes out as the equivalent of three spaces between the quote box and your text. So you don't actually need to put a space between the quote tag and what you're writing because the forum software will insert it for you. Did I confuse you enough?
ulysses Posted July 21, 2007 Posted July 21, 2007 There is this tip report that we generate in order for the staff to see what they make(because they pool). Once it's printed, we three hole punch it and place it in a binder for the waiters. At the top of the report it has the date and the shift: LUNCH/DINNER. Every day a different manager does the two reports and puts it out there; I am generally the administrator of this system. About six months into this project I looked at the book and at the top of all the reports the format of the dates was different: 3/5/07 Lunch, 6-Mar lunch, 3:6:07 Lunch and so on. It drove me crazy and then... I got it. This thing was mine, no triple spacing.
DonRocks Posted February 23, 2008 Author Posted February 23, 2008 Go to top of thread - triple spacing is becoming pandemic once again. New users, take note: U will be elektrokuted if U don't stop.
jparrott Posted February 23, 2008 Posted February 23, 2008 Go to top of threadPerhaps you should see post #28.Cheers, Corked-wine-breath (grrr)
DonRocks Posted September 28, 2008 Author Posted September 28, 2008 I'll pay for dessert. Note that Ack(4, 3) has about the same number of digits as the number in the attached file. I'm surprised Jake didn't win this competition.
jparrott Posted September 28, 2008 Posted September 28, 2008 U will be elektrokuted if U don't stop. U died 34 years ago http://en.wikipedia.org/wiki/U_Thant'>.
jparrott Posted April 15, 2009 Posted April 15, 2009 Guess I shouldn't've claimed this as income on my last taxes.
jparrott Posted July 16, 2012 Posted July 16, 2012 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DonRocks Posted March 11, 2014 Author Posted March 11, 2014 Allow me to endorse anything PF says about Paris. The PM he sent me before my trip in 2011 may be the best PM ever sent on DR.com. Second best.
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